Glossary entry

German term or phrase:

quotientengleich-produktgleich

English translation:

directly proportional -- inversely proportional

Added to glossary by janejira
Apr 5, 2012 03:09
12 yrs ago
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German term

quotientengleich-produktgleich

German to English Science Mathematics & Statistics Lernkompetenz
Hallo tolle Uebersetzer!
In Lernkompetenz fuer Mathe unter Bereich "Proportitionalitaet" der 7 Klasse steht es:

Die Begriffe "quotientengleich" und "produktgleich" kennen und anwenden.

Koennt ihr mir dabei helfen!
Change log

Apr 5, 2012 07:36: Steffen Walter changed "Field" from "Other" to "Science"

Proposed translations

+1
6 hrs
Selected

directly proportional -- inversely proportional

The definition of a directly proportional relationship is that the quotient remains the same (Quotientengleichheit). Similarly, the definition of an inversely proportional relationship is that the product remains the same (Produktgleichheit).
Peer comment(s):

agree Marcus Malabad
15 hrs
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4 KudoZ points awarded for this answer. Comment: "Super! Danke schoen!"
2 hrs

componendo and dividendo principle

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-1
7 hrs

proportional / non-proportional

In Class 7, they look at equal ratios e.g. 2/1 = 6/3 = 10/5. These result in linear graphs through the origin [points being e.g. (1,2) (3,6) (5,10) on line y=2x].

That's then extended to linear graphs that do not go through the origin [points being e.g. (1,3) (3,7) (5, 11) on line y=2x+1].

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Note added at 8 hrs (2012-04-05 12:00:38 GMT)
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Maybe it depends on the context but the following is a typical extract from a Klasse 7 syllabus and it's definitely talking about linear (and not inverse) functions

Inhalte
• Zuordnungen
• Zuordnungsvorschrift
• Zuordnungstabelle
• Darstellung im Koordinatensystem
• proportionale Zuordnung quotientengleich
• antiproportionale Zuordnung produktgleich

http://www.friesenschule.eu/arbpl/MA_07.pdf
Peer comment(s):

disagree Eric Zink : And where does produktgleich come in? It's definitely not non-proportional (in which case nothing would be gleich).
50 mins
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